Inverse Tree

Created by Paul Bourke
Contributed by Roger Bagula


This is a classic IFS series (xn+1,yn+1) = f(xn,yn).

f(x,y) is chosen from one of the following with equal probability.
f(x,y) = (x/2,y/2)
f(x,y) = (1/(x+1),y(y+1))
f(x,y) = (x/(x+1),1/(y+1))